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The sum of the numbers between 200 and 400 that are divisible by 7 is
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a
8729
b
7511
c
6328
d
5712
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Correct option is A
Required numbers are203,210,…,399 Now, 399=203+7(n−1)⇒57=29+(n−1)⇒n=29Thus required sum is =292[203+399]=8729Similar Questions
If the sum of first terms of an is , then the sum of squares of these terms is
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