Q.

The sum of the numbers between 200 and 400 that are divisible by 7 is

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a

8729

b

7511

c

6328

d

5712

answer is A.

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Detailed Solution

Required numbers are203,210,…,399 Now, 399=203+7(n−1)⇒57=29+(n−1)⇒n=29Thus required sum is =292[203+399]=8729
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