The sum of the real roots of the equation |x−2|2+|x−2|−2=0, is
We have,
|x−2|2+|x−2|−2=0=(|x−2|+2)(|x−2|−1)=0=|x−2|−1=0 [∵|x−2|+2+0]=x−2=±1⇒x=3,1
Sum of the roots = 4.