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Q.

Sum of the root of the equation 2sin2⁡θ+sin2⁡2θ=2;0≤θ≤π/2 is

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a

π/2

b

3π/4

c

7π/2

d

5π/12

answer is B.

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Detailed Solution

4sin2⁡θcos2⁡θ=21−sin2⁡θ⇒    2sin2⁡θ−1cos2⁡θ    =0⇒        sin2⁡θ    =1/2or cos2⁡θ    =0 ⇒        θ    =π/4 or    θ    =π/2
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