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Sum of the root of the equation $2 \sin^{2} θ + \sin^{2} 2 θ = 2; 0 \leq θ \leq π / 2$ is

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detailed solution

Correct option is B

4sin2⁡θcos2⁡θ=21−sin2⁡θ⇒ 2sin2⁡θ−1cos2⁡θ =0⇒ sin2⁡θ =1/2or cos2⁡θ =0 ⇒ θ =π/4 or θ =π/2

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Sum of the root of the equation 2sin2⁡θ+sin2⁡2θ=2;0≤θ≤π/2 is

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Sum of the root of the equation $2 \sin^{2} θ + \sin^{2} 2 θ = 2; 0 \leq θ \leq π / 2$ is