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Questions  

The sum of the roots of the equation 4cos3x4cos2xcos(π+x)1=0   in the interval [0, 315] is pπ where p is equal to 

a
2500
b
2550
c
2600
d
2651

detailed solution

Correct option is B

4cos3⁡x−4cos2⁡x+cos⁡x−1=0⇒ 4cos2⁡x+1(cos⁡x−1)=0⇒cos⁡x=1⇒x=2nπ100π<315<101π Required sum =2π+4π+…100π=2(1+2+…50)π=2×50×512π=2550π

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