The sum of the roots of the equation 4cos3x−4cos2x−cos(π+x)−1=0 in the interval [0, 315] is pπ where p is equal to
2500
2550
2600
2651
4cos3x−4cos2x+cosx−1=0⇒ 4cos2x+1(cosx−1)=0⇒cosx=1⇒x=2nπ100π<315<101π Required sum =2π+4π+…100π=2(1+2+…50)π=2×50×512π=2550π