Sum of the roots of the equation x2+|2x−3|−4=0 is

Case 1: When x<3/2 In this case the equation becomes ⇒    x2−(2x−3)−4=0⇒    x2−2x+1=2⇒    (x−1)2=2⇒x−1=±2⇒    x=1±2As x<3/2 we take, x=1-2Case 2: When x≥3/2 In this case the equation becomesx2+(2x−3)−4=0⇒(x+1)2=8⇒x+1±22As x≥3/2,x=−1+22Sum of the roots is                              (1−2)+(−1+22)=2.