Sum of the roots of the equation 4x−1x2−4x−1x+1=0  is

Put x−1x=t to obtain 4t2−4t+1=0⇒t=12,12Now, x−1x=12⇒x2−1x=12⇒ 2x2−x−2=0∴ Sum of roots of the given equation =12+12=1