Sum of roots is -1 and sum of their reciprocals is 16, then equation is

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x2+x-6=0

x2-x+6=0

6x2+x+1=0

x2-6x+1=0

answer is A.

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Detailed Solution

Let roots are α and β. Given α+β=-11α+1β=16⇒α+βαβ=16⇒αβ=-6Hence the equation, x2-(α+β)x+αβ=0⇒x2+x-6=0

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