Questions
The sum of the series is
a
−20C10
b
1220C10
c
0
d
20C10
detailed solution
Correct option is B
We know that,(1+x)20=20C0+20C1x+…+20C10x1+…+20C20x20 On putting x = -1, we get0=20C0−20C1+…−20C9+20C10−20C11+…+20C20⇒0=20C0−20C1+…−20C9+20C10−20C9+…+20C0 ∵nCr=nCn−r⇒ 0=2 20C0−20C1+…−20C9+20C10⇒ 20C10=2 20C0−20C1+…+20C10⇒ 20C0−20C1+…+20C10 =1220C10Talk to our academic expert!
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