First slide
Binomial theorem for positive integral Index
Question

The sum of the series  101C1 101C0+2101C2 101C1+3101C3 101C2++101.101C101 101C100 is __________.

Moderate
Solution

Here, Tr=r101Cr 101Cr1=r(101r+1)r=102r

  Given sum =r=1101(102r)                            =101+100+99++2+1                            =5151

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