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Questions  

The sum of the series cot12+cot18+cot118+cot132+ is

a
π2
b
π4
c
π6
d
none of these

detailed solution

Correct option is B

The given series=cot−1⁡2(1)2+cot2⁡2(2)2+cot−1⁡2(3)2+cot−1⁡2(4)2+…∴Tn=cot−1⁡2n2=tan−1⁡12n2 =tan−1⁡(2n+1)−(2n−1)1+(2n+1)(2n−1) =tan−1⁡(2n+1)−tan−1⁡(2n−1)∴T1=tan−1⁡3−tan−1⁡1T2=tan−1⁡5−tan−1⁡3T3=tan−1⁡7−tan−1⁡5and so on.∴Sn=tan−1⁡(2n+1)−tan−1⁡1∴limn→∞ Sn=tan−1⁡∞−π4=π2−π4=π4

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