The sum of the the series cot−12+cot−18+cot−118+cot−132+…….. is
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a
π2
b
π4
c
π6
d
none of these
answer is B.
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Detailed Solution
The given series=cot−12(1)2+cot22(2)2+cot−12(3)2+cot−12(4)2+…∴Tn=cot−12n2=tan−112n2=tan−1(2n+1)−(2n−1)1+(2n+1)(2n−1)=tan−1(2n+1)−tan−1(2n−1)∴T1=tan−13−tan−11, T2=tan−15−tan−13,T3=tan−17−tan−15and so on.∴Sn=tan−1(2n+1)−tan−11∴limn→∞ Sn=tan−1∞−π4=π2−π4=π4