Q.
Sum of the series 11n−1+13n−3+15n−5+.....+1n−11 is
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a
2n−1n−1
b
2n−1n
c
2nn−1
d
2nn
answer is B.
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Detailed Solution
Sn=1n[n1+n(n−1)(n−2)3+n(n−1)(n−2)(n−3)(n−4)5+.....] =1n[nC1+nC3+nC5+....]=1n[C1+C3+C5+....]=1n2n−1 .
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