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The sum of the series 5 +55 +555 +...to n terms is
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a
18010n+1
b
58110n+1−9n−10
c
58110n−1−8n−1
d
58110n+1+9n+10
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Correct option is B
5 + 55 + 555 +...to n terms=5 {1+ 1 1 + 1 1 1 +...to n terms} =59{9+99+999+… to n terms }[multiply numerator and denominator by 9]=59{(10−1)+(100−1)+(1000−1)+… to n terms }=59{10+100+1000+…+n terms −(1+1+…+n terms )}=591010n−110−1−n=58110n+1−10−9nSimilar Questions
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