The sum of the series ∑r=015Cr 30
229+12 C15 30
230+12 C15 30
229+ C15 30
229+ C15 302
Let S=∑r=015 Cr 30=C0 30+C1 30+C2 30+....+C15 30
Also S=C30 30+C29 30+C28 30+....+C15 30 ∵Cr n=Cn−r n_____________________________________________ By adding 2S=C0 30+C1 30+....+C30 30+C15 30
2S=230+C15 30 ⇒S=229+C15 302