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The sum of the series $\sum_{r = 0}^{10}^{20} C_{r'}$ is

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220

219

219+1220C10

219−1220C10

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detailed solution

Correct option is C

∑r=010 20Cr 20C0+20C1+…+20C10=122 20C0+20C1+…+20C10=22 20C0+20C1+…+20C10+ 20C20+20C19+…+20C10=12 20C0+20C1+…+20C10+20C11+…+20C20+20C10=12220+20C10=219+1220C10

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The sum of the series ∑r=010 20Cr′ is

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The sum of the series $\sum_{r = 0}^{10}^{20} C_{r'}$ is