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Questions  

Sum of the series r=1nr(r+1)! is

a
1−1n!
b
1−1(n+1)!
c
2−1(n+1)!
d
none of these

detailed solution

Correct option is B

Let tr denote the rth term of the series, then tr=r(r+1)!=r+1−1(r+1)!=1r!−1(r+1)!⇒∑r=1n tr=∑r=1n 1r!−1(r+1)!=1−1(n+1)!

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