Q.
The sum of the series S=20C0−20C1+20C2−20C3+…+20C10 is
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a
− 20C10
b
12 20C10
c
0
d
20C10
answer is B.
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Detailed Solution
Using nCr=nCn−r, we can write 2S=20C0−20C1+20C2−20C3+…20C10+20C20−20C19+ 20C18−…+20C10⇒ S=0+12 20C10=12 20C10
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