The sum of the series S=∑r−1n logar+1br−1 is
n2logan−1bn
n2logan+3bn−1
n2logan+2bn−1
none of these
S=∑r=1n [(r+1)loga−(r−1)logb].
=n2[(2+n+1)loga−(0+n−1)logb]
=n2logan+3bn−1