Sum of the series S=1+12(1+2)+13(1+2+3)+14(1+2+3+4)+…up to 20 terms is
110
111
115
116
Let tk denote the kth term of the series. Then
tk=1k(1+2+3+…+k)=1kk(k+1)2=k+12.
Thus, S=12[2+3+4+…+21]=102(2+21)=115