First slide
Series of natural numbers
Question

 The sum of the series 3×1312+513+2312+22+713+23+3312+22+32++ upto to 10th  term is 

Moderate
Solution

Tn=2n+1nn+122nn+12n+16=32n2+nS10=T10=32110n2+110n=3210×11×216+10×112=660

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