The sum of the series 1+3x+6x2+10x3+…∞ will be
1(1−x)2
11−x
1(1+x)2
1(1−x)3
Let S=1+3x+6x2+10x3+…∞
xS=x+3x2+6x3+…∞
On subtracting, we get
S(1−x)=1+2x+3x2+4x3+…∞x(1−x)S=x+2x2+3x3+…∞
Again on subtracting, we get
S[(1−x)−x(1−x)]=1+x+x2+x3+…∞
⇒ S[(1−x)(1−x)]=11−x⇒S=1(1−x)3