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The sum of series x1x2+x21x4+x41x8+to infinite terms, if f|x|<1 is 

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a
11−x
b
x1−x
c
11+x
d
x1+x

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detailed solution

Correct option is B

We have,tn=x2n−11−x2n−1=1+x2n−1−11+x2n−11−x2n−1=11−x2n−1−11−x2nTherefore,Sn=∑n=1n tn=11−x−11−x2+11−x2−11−x4 +…+11−x2n−1−11−x2n =11−x−11−x2n


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The value of the sum i=120i1i+1i+1+1i+2++120 is


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