The sum of 162th power of the roots of the equation x3−2x2+2x−1=0is

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answer is 3.

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Detailed Solution

The given equation is x3−2x2+2x−1=0( x3-1)-2xx-1=0(x-1)x2-x+1=0x=1,x=-w,-w2α162+β162+γ162=1+w354+w654 =1+1+1=3The value is 3.

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