Q.

The sum to 10 terms of the series 2+6+18+54+… is

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a

121(6+2)

b

1212(3+1)

c

243(3+1)

d

243(3−1)

answer is A.

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Detailed Solution

a=2,r=3S10=ar10−1r−1=235−13−1=2(242)(3+1)(3−1)(3+1)=121(6+2)
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