Q.
The sum to 10 terms of the series 2+6+18+54+… is
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a
121(6+2)
b
1212(3+1)
c
243(3+1)
d
243(3−1)
answer is A.
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Detailed Solution
a=2,r=3S10=ar10−1r−1=235−13−1=2(242)(3+1)(3−1)(3+1)=121(6+2)
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