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The sum to 10 terms of the series $\sqrt{2} + \sqrt{6} + \sqrt{18} + \sqrt{54} + \dots$ is

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121(6+2)

1212(3+1)

243(3+1)

243(3−1)

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detailed solution

Correct option is A

a=2,r=3S10=ar10−1r−1=235−13−1=2(242)(3+1)(3−1)(3+1)=121(6+2)

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The sum to 10 terms of the series 2+6+18+54+… is

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The sum to 10 terms of the series $\sqrt{2} + \sqrt{6} + \sqrt{18} + \sqrt{54} + \dots$ is