The sum of values of x satisfying the equation (31+815)x2−3+1=(32+815)x2−3 is
3
0
2
none of these
(31+815)x2−3+1=(32+815)x2−3or (31+815)x2−3+1x2−3=(32+815)x2−3or x2−3=1 or x=±2 ∵an+bn=(a+b)n