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Suppose a1,a2,are in A.P. If a8 : a5=3 : 2,  a17 : a23 is

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a
1 : 2
b
3 : 4
c
4 : 11
d
8 : 11

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detailed solution

Correct option is B

Let a be the first term and d be the commondifference of the A.P. a1, a2, a3,… Then 32=a8a5=a+7da+4d⇒ 3a+12d=2a+14d⇒a=2dNow, a17a23=a+16da+22d=2d+16d2d+22d=1824=34


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The sum of n terms of an A.P. is 3n2+5 The number of  term which equals 159, is


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