Suppose α,β are roots of ax2+bx+c=0
then roots of a(x−2)2−b(x−2)(x−3)+c(x−3)2=0 are
2+α1+β,2+β1+α
2+α3+β,3+α2+β
2+3α2+α,2+3β2+β
2+3α1+α,2+3β1+β
Write the equation as
a−x−2x−32+b−x−2x−3+c=0
Now, −x−2x−3=α,β
⇒ x=2+3α1+α,2+3β1+β