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Suppose A, B are two 3×3 matrices such that A–1 exists. Then  (AB)A1(A+B) is equal to 

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a
(A+B)A−1(A−B)
b
A−1B+B2
c
I−BAB−1(A−B)
d
I+BAB−1(A+B)

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detailed solution

Correct option is A

(A−B)A−1(A+B)=I−BA−1(A+B)=A+B−BA−1A−BA−1B=A−BA−1B=A+B−BA−1A−BA−1B=(A+B)−BA−1(A+B)=(A+B)I−BA−1=(A+B)A−1(A−B)


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