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$Suppose A, B are two points on 2 x - y + 3 = 0 and P (1, 2) is such that P A = P B, then the$ $mid-point of A B is$

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−75,95

75,−95

−75,−95

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Correct option is A

Equation of AB is 2x−y+3=0 We have ΔPAD≅△PBD ⇒D is foot of perpendicular from P to AB ⇒α−12=β−2−1=−[2×1−1×2+3]4+1⇒α−12=β−2−1=−35α=−15;β=135D=(α,β)=−15,135

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Suppose A,B are two points on 2x−y+3=0 and P(1,2) is such that PA=PB , then the mid-point of AB is

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$Suppose A, B are two points on 2 x - y + 3 = 0 and P (1, 2) is such that P A = P B, then the$ $mid-point of A B is$