Questions
Supposeare two real numbers and . Let
If then is equal to
detailed solution
Correct option is A
Δ=1+1+11+α+β1+α2+β21+α+β1+α2+β21+α3+β31+α2+β21+α3+β31+α4+β4=1111αβ1α2β21111αβ1α2β2=Δ12where Δ1=1111αβ1α2β2Applying C3→C3−C2 and C2→C2−C1 we getΔ1=1001α−1β−α1α2−1β2−α2=(α−1)(β−α)11α+1β+α=(α−1)(β−1)(β−α)Thus Δ=(α−1)2(β−1)2(α−β)2∴ k=1Similar Questions
If ,then is equal to
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