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Suppose a, b, c are in A.P. and , are in G.P . If then the value of a, is
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a
122
b
123
c
12−13
d
12−12
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Correct option is D
It is given that a, b, c are in A.P. ⇒2b=a+c⇒2b=32−b [∵a+b+c=32(Given)]⇒ b=12⇒a+c=1 [∵a+c=2b]It is also given that a2,b2,c2 are in G.P.⇒b2=a2c2⇒b2=±ac⇒ac=±14 [∵b=12]CASE I: When ac =½ In this case, we have ac=14and a+c=1∴ a+14a=1⇒(2a−1)2=0⇒a=12 Thus, we have a = c =b =½ which is not possible as aSimilar Questions
If there successive terms of a G.P with common ratio r(r>1) form the sides of a and [r] denotes greates integer function, then
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