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Suppose $a, b, c,$ are in A.P. and $- 1 < a, b, c,$ Let $x = \sum_{n = 0}^{\infty} a^{n}, y = \sum_{n = 0}^{\infty} b^{n}, z = \sum_{n = 0}^{\infty} c^{n},$ then $x, y, z$ are in

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Correct option is C

We have x=11−a, y=11−b, z=11−c.As a, b, c are in A.P., -a, -b, -c are in A.P.⇒ 1-a, 1-b, 1-c are in A.P.⇒11−a,11−b,11−care in H.P.

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Suppose a, b, c, are in A.P. and -1<a,b,c, Let x=∑n=0∞ an,y=∑n=0∞ bn,z=∑n=0∞ cn, then x,y,z are in

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Suppose $a, b, c,$ are in A.P. and $- 1 < a, b, c,$ Let $x = \sum_{n = 0}^{\infty} a^{n}, y = \sum_{n = 0}^{\infty} b^{n}, z = \sum_{n = 0}^{\infty} c^{n},$ then $x, y, z$ are in