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Tangents and normals

Question

Suppose  a, b, c are such that the curve y=ax2+bx+c is y=3x-3at1,0 and is also tangent to y=x+1at3,4 Then the value of 2a-b-4c equals _____

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Solution

y=ax2+bx+c,dydx=2ax+bWhenx=1,y=0a+b+c=01dydxx=1=3anddydxx=3=12a+b=326a+b=13Solving1,2and3,a=-12,b=4,c=-722a-b-4c=-1-4+14=9



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