First slide
Algebra of complex numbers
Question

Suppose a,b,cC,and |a|=|b|=|c|=1 and abc=a+b+c then bc+ca+ab is equal to

Moderate
Solution

|a|2=|b|2=|c|2=1

     aa¯=bb¯=cc¯=1

Now,       abc=a+b+c

     a¯b¯c¯=a¯+b¯+c¯

    1abc=1a+1b+1c     bc+ca+ab=1

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