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Suppose a,b,cC,and |a|=|b|=|c|=1 and abc=a+b+c then bc+ca+ab is equal to

a
0
b
-1
c
1
d
none of these

detailed solution

Correct option is C

|a|2=|b|2=|c|2=1    ⇒ aa¯=bb¯=cc¯=1Now,       abc=a+b+c⇒     a¯b¯c¯=a¯+b¯+c¯⇒    1abc=1a+1b+1c⇒     bc+ca+ab=1

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