Suppose a,b,c∈C,and |a|=|b|=|c|=1 and abc=a+b+c then bc+ca+ab is equal to
0
-1
1
none of these
|a|2=|b|2=|c|2=1
⇒ aa¯=bb¯=cc¯=1
Now, abc=a+b+c
⇒ a¯b¯c¯=a¯+b¯+c¯
⇒ 1abc=1a+1b+1c⇒ bc+ca+ab=1