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Suppose a,b,c>0 and a,b,c c are the pth, qth, rth terms of a G.P. Let Δ=1    p    loga1    q    logb1    r    logc then numerical value of  is

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detailed solution

Correct option is C

Let a=ARp−1,b=ARq−1and c=ARr−1⇒log⁡a=α+(p−1)β,log⁡b=α+(q−1)β andlog⁡c=α+(r−1)βwhere        α=log⁡a,β=log⁡RNow,           Δ=1pα+(p−1)β1qα+(q−1)β1rα+(r 1)βUsing C3→C3−(α−β)C1−βC3, we get Δ=0


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