Suppose a,b,c>0 and a,b,c c are the pth, qth, rth terms of a G.P. Let Δ=1 p loga1 q logb1 r logc then numerical value of ∆ is
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a
-1
b
2
c
0
d
none of these
answer is C.
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Detailed Solution
Let a=ARp−1,b=ARq−1and c=ARr−1⇒loga=α+(p−1)β,logb=α+(q−1)β andlogc=α+(r−1)βwhere α=loga,β=logRNow, Δ=1pα+(p−1)β1qα+(q−1)β1rα+(r 1)βUsing C3→C3−(α−β)C1−βC3, we get Δ=0