Suppose a,b,c>0 and a,b,c c are the pth, qth, rth terms of a G.P. Let Δ=1 p loga1 q logb1 r logc then numerical value of ∆ is
-1
2
0
none of these
Let a=ARp−1,b=ARq−1and c=ARr−1
⇒loga=α+(p−1)β,logb=α+(q−1)β and
logc=α+(r−1)β
where α=loga,β=logR
Now,
Δ=1pα+(p−1)β1qα+(q−1)β1rα+(r 1)β
Using C3→C3−(α−β)C1−βC3, we get Δ=0