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Suppose $a, b, c > 0$ and $p \in R .$ If
$(a^{2} + b^{2}) p^{2} - 2 (a b + b c) p + (b^{2} + c^{2}) = 0$
then $a, b, c$ are in

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Correct option is B

Write (1) as a2p2−2abp+b2+b2p2−2bcp+c2=0⇒ (ap−b)2+(bp−c)2=0As ap−b,bp−c∈R.from (2), we get ap−b=0,bp−c=0⇒ p=ba=cb⇒ a, b, c are in G.P.

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Suppose a, b, c>0 and p∈R. Ifa2+b2p2−2(ab+bc)p+b2+c2=0then a, b, c are in

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Suppose $a, b, c > 0$ and $p \in R .$ If
$(a^{2} + b^{2}) p^{2} - 2 (a b + b c) p + (b^{2} + c^{2}) = 0$
then $a, b, c$ are in