Suppose A is a complex number and n∈N, such that An = (A + 1)n = 1, then the least value of n is
3
6
9
12
Let A = x + iy. Given,
|A|=1⇒x2+y2=1
and |A+1|=1⇒(x+1)2+y2=1
⇒ x=−12 and y=±32⇒ A=ω or ω2⇒ (ω)n=(1+ω)n=−ω2n
Therefore, n must be even and divisible by 3.