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Suppose E and F are two events of a random experiment. If the probability of occurence of E is 15  and the probability of occurence of F given E is 110 . Then the probability of non-occurance of atleast one of the events E and F is                           

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a
118
b
12
c
4950
d
150

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detailed solution

Correct option is C

Given that: P(E)=15 ;   P(F/E) = 110                        P(F∩E) = PEPFE=150  P(F¯ ∪ E¯) = 1−P(E∩F)                    = 1− 150 = 4950


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