Suppose E and F are two events of a random experiment. If the probability of occurence of E is 15 and the probability of occurence of F given E is 110 . Then the probability of non-occurance of atleast one of the events E and F is

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118

4950

150

answer is C.

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Detailed Solution

Given that: P(E)=15 ; P(F/E) = 110 P(F∩E) = PEPFE=150 P(F¯ ∪ E¯) = 1−P(E∩F) = 1− 150 = 4950

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