Questions
a
f(x) ≤ min(ax, bx)
b
f(x) ≥ max(ax, bx)
c
a ≤ f(x) ≤ b
d
ax ≤ f(x) ≤ bx
detailed solution
Correct option is D
For x > 0. Applying Lagrange’s theorem on [0, x] we have c ∈ (0, x)such that f(x)x = f(x)−f(0)x−0 = f'(c) But a≤f′(c)≤b so a≤f(x)x≤b⇒ax≤f(x)≤bx,x>0 Similarly for x<0_ applying Lagrange's theorem for [x,0⌉, we have ax≤f(x)≤bxTalk to our academic expert!
Similar Questions
Consider the function on the interval the value of c satisfying the conclusion of Lagrange’s mean value theorem is ______________.
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