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 Suppose 'a' is a fixed real number such that axpx=ayqy=azrzif p, q, r are in AP then x, y, z all are in 

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A.P
b
G.P
c
H.P
d
A.G.P

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detailed solution

Correct option is C

p−q=q−r=klet⇒ax−1p=ay−1q=az−1r⇒ax−1−ay−1p−q=ay−1−az−1q−r By law of proportion ⇒1x−1y=1y−1z


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Given that α,γ are roots of the equation Ax24x+1=0,  and β,δ the roots of the equation of Bx26x+1=0,  such that α,β,γ,  and δ  are in H.P., then


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