Suppose that a function f:R→R satifies f(x+y)=f(x)f(y) for all x,y∈R and f(1)=3 . If ∑i=1nf(i)=363, then n is equal to..........
f(x+y)=f(x)f(y)⇒f(x)=axf(x)=3⇒a=3∴f(x)=3x Now ∑i=1nf(i)=363⇒3+32+33+….. nterms =363 ⇒33n-13-1=363⇒3n=243⇒n=5