Suppose that the graph of y=f(x), contains the points (0, 4) and (2, 7). If f' is continuous then ∫02 f′(x)dx is equal to
2
-2
3
none of these
f(0)=4,f(2)=7 and ∫02 f′(x)dx=f(2)−f(0)= 7−4=3