Q.

Suppose a∈I and the equation (x-a) (x-5) = 3 has integral roots, then the set of values which ‘a ’ can take is:

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{-11, - 13}

{3,7}

{-3,-7}

answer is 3.

(Detailed Solution Below)

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Detailed Solution

Let m ∈I be a root of (x - a) (x-5) = 3.then(m-a) (m -5) = 3As m-a and m - 5 are integers, m−5=±1 or m−5=±3⇒m= 2, 4, 6, 8.Thus, a = 3,7.

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