First slide
Applications of determinant
Question

Suppose A=aij3×3, where aijR If det(adjA)=25 then |det (A)| equals:

Moderate
Solution

Using det(adjA)=(det(A))2 we get

(det(A))2=25|det(A)|=5

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App