Suppose (m+n)th term of a G.P. is p and (m – n)th term is q, then its nth is
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a
pq
b
pqpm/n
c
pqpm/2n
d
pq
answer is C.
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Detailed Solution
Let a be the first term and r be the common ratio.We have p=am+n=arm+n−1 q=am−n=arm−n−1⇒ pq=am+nam−n=r2n⇒r=pq1/2nNow, an=arn−1=arm+n−1rm=ppq−m/2n=pqpm/2n