Questions
Suppose th term of an A.P. is 1/n and th term of the is 1/m. If th term of the is 1, then is equal to
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a
mn
b
m+n
c
m–n
d
m+n –1
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Correct option is A
Let d be the common difference of the A.P., then (m−n)d=am−an=1n−1m⇒ d=1mnNow ar−am=(r−m)d⇒ 1=ar=1n+(r−m)1mn=rmn⇒ r=mn.Similar Questions
The sum of terms of an is The number of term which equals 159, is
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