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Suppose $p \in N, n =^{P} C_{2} x$ and $m =^{n} C_{2}$ if $4 m : n =$ $18 : 1,$ then $p$ is equal to

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Correct option is D

m=12n(n−1)⇒4mn=2(n−1)=p(p−1)−2∴18=p(p−1)−2⇒p=5

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Suppose p∈N,n=PC2x and m=nC2 if 4m:n=18:1,then p is equal to

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Suppose $p \in N, n =^{P} C_{2} x$ and $m =^{n} C_{2}$ if $4 m : n =$ $18 : 1,$ then $p$ is equal to