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Suppose $p \in R .$ If the fourth term in the expansion of ${(p x + \frac{1}{x})}^{n}$ is $\frac{5}{2}$ then $(n, p)$ is equal to:

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detailed solution

Correct option is B

T4=nC3(px)n−31x3=nC3pn−3xn−6=52⇔n−6=0 and 6C3p3=52⇔n=6,p=1/2

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Suppose p ∈ R. If the fourth term in the expansion of px+1xn is 52 then (n, p) is equal to:

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Suppose $p \in R .$ If the fourth term in the expansion of ${(p x + \frac{1}{x})}^{n}$ is $\frac{5}{2}$ then $(n, p)$ is equal to: