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Suppose two cubic polynomials f(x) and g(x) satisfying the following f(2)=g(4),f(4)=g(8),f(8)=g(16),f(16)=g(32)+64 then the value of 110(f(64)-g(128)) equals

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answer is 992.

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Detailed Solution

Let hx=fx−g2xh2=0,h4=0,h8=0,h16=64suppose hx=kx−2x−4x−8use h16=64,to get the value of khx=121x−2x−4x−8Therefore, h64=9920

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