$\text{ Suppose two cubic polynomials }f\left(x\right)\text{ and }g\left(x\right)\text{ satisfying the following }$$f\left(2\right)=g\left(4\right),f\left(4\right)=g\left(8\right),f\left(8\right)=g\left(16\right),f\left(16\right)=g\left(32\right)+64\text{ then the value of }$$\frac{1}{10}\left(f\right(64)-g(128\left)\right)\text{ equals }$