Suppose x and y are real numbers such that tan x + tan y = 42 and cot x + cot y = 49. Then the value of tan(x + y) is __________ . 

$\begin{array}{l}\cot \mathrm{x}+\cot \mathrm{y}=49\\ \mathrm{or} \frac{1}{\tan \mathrm{x}}+\frac{1}{\tan \mathrm{y}}=49\\ \mathrm{or} \frac{\tan \mathrm{y}+\tan \mathrm{x}}{\tan \mathrm{x} \tan \mathrm{y}}=49\\ \mathrm{or} \tan \mathrm{x} \tan \mathrm{y}=\frac{\tan \mathrm{x}+\tan \mathrm{y}}{49}=\frac{42}{49}=\frac{6}{7}\\ \therefore \tan (\mathrm{x}+\mathrm{y})=\frac{42}{1-(6/7)}=\frac{42}{1/7}=294\end{array}$